Calender & Time
Ordinary/Normal Year:
A normal Year contains 365 days i.e. 52 weeks and a day
Leap Year:
Leap Year contains 366 days i.e. 52 weeks and two days(As february contains 29 days).
How to Check if a Year is Leap or Not?
Example:
Calender Year:
Calender Year Starts from January & ends with December
Financial Year:
Finacial Year Starts from 1st Year April and ends with 31st March
Counting of Odd Days:
Day of the Week Related to Odd Days:
Number of Odd Day |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
Day |
Sunday |
Monday |
Tuesday |
Wednesday |
Thursday |
Friday |
Saturday |
Examples:
Example 1:
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
a) Sunday
b) Saturday
c) Friday
d) Wednesday
Solution:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Example 2:
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
a) Sunday
b) Saturday
c) Tuesday
d) Wednesday
Solution:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Example 3:
If your birthday, 30th June 1995 falls on Friday, on what day of the week does your birthday fall in the year 1997.
Solution:
1995 is an ordinary year. Therefore it consists of 1 odd day. But 1996 is a leap year, and it consists of 2 odd days. Therefore, there is 3 odd days.
Your birthday in 1997 will be 3 days after Friday, i.e. on Monday.